Suppose we place two 8-chip modules in the location where the barrel
layers will be later. How many tracks will these modules see?
The short anwer is: for a central Au-Au collision, a module
measuring 64mm by 7.0 cm located at 2.5cm would see 94 tracks,
and such a unit at 5.0 cm would see 29 tracks.
This scales of course roughly with 1/r2
The vertex resolution in Z is roughly the pixel size (400 um) divided by
sqrt(12), divided by sqrt(number of particles)
| |
Here are the details, showing cumulative cuts: AncSvx->Draw("YGLOBAL:XGLOBAL"," abs(LAYER)<=4") There are 21980 entries from 2 central AuAU events. | |
AncSvx->Draw("YGLOBAL:XGLOBAL"," LAYER==1 && EVENT>0") | |
AncSvx->Draw("YGLOBAL:XGLOBAL"," LAYER==1 && EVENT>0 && abs(ZGLOBAL)<3.5") | |
AncSvx->Draw("YGLOBAL:XGLOBAL"," LAYER==1 && EVENT>0 && abs(ZGLOBAL)<3.5 && abs(YGLOBAL)<0.32") | |
AncSvx->Draw("YGLOBAL:XGLOBAL"," LAYER==1 && EVENT>0 && abs(ZGLOBAL)<3.5 && abs(YGLOBAL)<0.32 && XGLOBAL>0") Layer 1 is at 2.5 cm. | |
AncSvx->Draw("YGLOBAL:XGLOBAL"," LAYER==2 && EVENT>0 && abs(ZGLOBAL)<3.5 && abs(YGLOBAL)<0.32 && XGLOBAL>0") Layer 2 is at r=5 cm. |
Short answer: Per AuAu collision, 82 tracks
will be seen by 4 planes
of the ldrd detector
Details: Bounded by bottom of station 1, top of station 4. Cut at station 4: y>6.4cm Station 1 bound y<8.7cm | |
166 entries in station 4, for y>6.4 (so that they also hit station 1 | |
Bounded by layer 4, x<3.5, which is x<1.97 cm at station 1 | |
163 entries in station 1, for y<8.7 (so that they also hit
station 4, and abs(x)<1.97. This is statistically the same as
we saw in station 4.
The same procedure requiring track to go through stations 1-3 only (|x|<2.26, y<10.20)gives 198 hits. (99 per event) |