IFVTX acceptance

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Throw 10k events from z=0, each with a single 5GeV muon, into a 35° cone to the North. The plot shows the (non-zero) number of ifvtx layers hit. We are interested in 3 or more hits on a track - the blue area. The sum of the entries is 582.

We have to correct for a 12° hole in the acceptance (~12%), so 6.6% of tracks in the muon acceptance hit >=3 layers.

Files:
cfmgmc.input
ifvtx_acc.C

layer hit: layer 9-10 == station 1-4
Same events for the FVTX. The plot shows the (non-zero) number of fvtx layers hit. We are interested in 3 or more hits on a track - the green area. The sum of the entries is 4716.

So when making comparisons between the FVTX and the IFVTX, the acceptance ratio is 582/4716 = 12.3% (of the North-arm accaptance alone).




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