The Current Best Answers

Poor Deuterium (Data Sets 1,8-11) -> .1589305 g/cm^3
Good Deuterium (Data Sets 2-7)	  -> .1627605 g/cm^3

Hydrogen -> .070708 g/cm^3


Poor Deuterium (Data Sets 1,8-11) 
==========================================================

	percent	uncertainty
	------- -----------
D2	94.9  	   		Notes: - Percent is by Volume.
HD	 1.94  	.02 		       - This is from DS1 LD2. 
H2	 3.12	.06		       - P. 82 of Log 2.

H2O	  .014	.005
N2	  .014	.002
O2	  .0015	.0005
Ar	  .0002	.0001
CO2	  .0016	.0008


Good Deuterium (Data Sets 2-7)
============================================================

	percent	uncertainty
	------- -----------
D2	99.9  	.1   		Notes: - Percent is by Volume.
HD	   0  	 		       - This is from DS2-7 LD2. 
H2	   0			       - P. 216 of Log 3.

H2O	  <.04
HDO	  <.03	
N2	  .018	.004
O2	  .0037	.0004
Ar	  <.002
CO2	  <.003

Hydrogen 
=============================================================
Assumption 100%


Liquid Hydrogen Pressure-Temperature-Volume
=============================================================

	Temp	Press	Volume
	(R)	(PSIA)	CuFt/LB
	-----	-----	------
	34	9.527	.22160
	35	11.416	.22342	
	36	13.561	.22534
	37	15.984	.22735
	38	18.694	.22946
	39	21.723	.23170

I fit these 6 points (press vs. volume) using PAW.  The equation 
of the fit is:  
		V = .21147 + (.11713e-2)P + (-.11089e-4)P^2

With this equation the Volume at 15 psi is .22654 FT^3/LB.

This 'Volume' is really 1/density. 

So the density of LH2 at 15 psi at 36.6 Rankine is .070708 g/cm^3. 
       -------------		  		   ---------------

	Compare this to the value from PDB of  .0708


Liquid Deuterium Temperature-Pressure-Density
==================================================================

	Temp	Press	Density
	 (K)	(ATM)	Mol/Liter
	----	-----	-------
	21	.42405	41.9781
	22	.59925	41.4228
	23	.82353	40.8403	
	24     1.10456	40.2287
	25     1.45018	39.5858
	26     1.86843	38.9085

I fit these 6 points (press vs. density) using PAW.  The equation 
of the fit is:  
		d = 43.291 + (-3.4176)P + (.57834)P^2

With this equation the density at 15 psi (1.0206859 ATM) is 
40.405218 Moles/Liter.

1 Mole deuterium = 4.02820 grams.

So the density of LD2 at 15 psi at 23.7 K  is .1627605 g/cm^3. 
       --------------		  	      ---------------

	Compare this to the value from PDB of  .162



Deuterium Target Densities
========================================================================
For the poor LD2:

	(.949)(.1627605) + (.0194)(.1627605 + .070708)/2 + (.0312)(.070708)

	= .1589305 g/cm^3

For the good stuff:

	Assuming 100% LD2:  = .1627605 g/cm^3


BY:  RST
Last Updated:  22 JUL 97